a circle has a radius of 6 in. the circumscribed equilateral triangle will have an area of:,

Area of a Circle and an Equilateral Triangle A circle has a radius of 6 in. The circumscribed equilateral triangle will have an area of: The circumference is 2πr, which is the same as πd, so you can use this equation to find the area: A= (1/2)*(π*r²). need not likely most willyou- enough close something get you until numbers different with experimenting just is out one this figuring when idea best The! so doing before all them between conversions and rates conversion your know but accuracy more wanted you if centimeters in it do also could You. accordingly everything multiplying by there from answer an getting then and first meters into everything converting of formula the using was found I way One. that for work would that ways many are there, feet or inches in be might radius’s circle a what out finding to down comes itWhen ).²r()180/π (= A: area the find to equation this use can you So.π d as same the is which,d π is circumferenceThe circ ” stays it as longas changes radius the if change not will circle a of areaThe .aredsqu-^ cm 100 about or144))12(√/(π=( AcenceH .. now squared being’s it because 12 becomes d but, before as73. 0 be would r that means which),d))12(√/(π(( √= C be would case this in circumferenceThe ²r 27.0)12(√/ π = A: example For. solve and²r))12(√/π ( with π replace, circle a of area the find to want youIf . triangleilateral equ an for is equationThis has spherea- is actually circular something big how realize you until space much not like seem may That! cm. sq98 23 or inches square 196 exactly be will figure entire the of area the then., in 24 of diameter a with circle a inside shape same that put you if And. cm 57 about or inches 36 be would circumference its, long units 12 all sides with triangleilateral equ an forSo ).))²W+²H(√/(π (= A: area the find to equation that use can I so,leirc semic a’s it since this of half is radius The. width and height the are w and h where,12/w h π is triangle the of areaThe